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How does the term sin (2*pi*f*t) come from? I know that sin and cosine take radians as arguments which will be (pi/2) * (no. of degrees) but why do we mulitply f*t?
SOLVED: Using separation of variables method to solve the IBVP Utt = Uxx; 0 <x<1 t>0 u(o,t)=0=u(1,t) u(x, 0) = 2 sin (Tx) 4(x, 0) = sin (2tx) produces the general solution
![Find the absolute maximum and minimum value of f on [0, pi/2]. F(t) = 2 cos t + sin 2t - YouTube](https://i.ytimg.com/vi/gjDlr4Igtww/maxresdefault.jpg "Find the absolute maximum and minimum value of f on [0, pi/2]. F(t) = 2 cos t + sin 2t - YouTube")
Find the absolute maximum and minimum value of f on [0, pi/2]. F(t) = 2 cos t + sin 2t - YouTube
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![The set of values of x in [ 0,2π] for which fx=√sin x+cos x is defined is](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1418755/original_sinx.png "The set of values of x in [ 0,2π] for which fx=√sin x+cos x is defined is")
The set of values of x in [ 0,2π] for which fx=√sin x+cos x is defined is
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How does the term sin (2*pi*f*t) come from? I know that sin and cosine take radians as arguments which will be (pi/2) * (no. of degrees) but why do we mulitply f*t?
Plot of sin(2*Pi*t)
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